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What does System.out.printf( “%-15s%03d\n”, s1, x) do? Explain

by Anup Maurya
4 minutes read

In this article we’ll discuss What does System.out.printf( “%-15s%03d\n”, s1, x) do in context with Java Programming Language.

What does System.out.printf( “%-15s%03d\n”, s1, x) do ?

System.out.printf() is a method in Java that is used to print formatted output to the console. The format string passed to printf() specifies the format of the output.

Let’s break down the format string in the example provided:

%-15s%03d\n

%-15s specifies a string (s) to be left-justified (-) in a field of 15 characters. The % symbol indicates that a value will be substituted into this field at runtime.

%03d specifies an integer (d) to be displayed with leading zeros (0) if it has fewer than three digits. The 3 specifies the minimum field width, and the % symbol indicates that a value will be substituted into this field at runtime.

\n specifies a newline character, which will cause the output to be printed on a new line.

So, when we call System.out.printf("%-15s%03d\n", s1, x), the value of the string s1 will be left-justified in a field of 15 characters, and the value of the integer x will be displayed with leading zeros if it has fewer than three digits. The output will be printed on a new line.

For example, if we have s1 = "hello" and x = 42, the output will be:

hello          042

Note that the value of s1 is left-justified in a field of 15 characters, and the value of x is displayed with leading zeros to make a field width of 3.

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